-16x^2=-35x+3.5

Solution for -16x^2=-35x+3.5 equation:

-16x^2=-35x+3.5

We move all terms to the left:

-16x^2-(-35x+3.5)=0

We get rid of parentheses

-16x^2+35x-3.5=0

a = -16; b = 35; c = -3.5;
Δ = b2-4ac
Δ = 352-4·(-16)·(-3.5)
Δ = 1001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-\sqrt{1001}}{2*-16}=\frac{-35-\sqrt{1001}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+\sqrt{1001}}{2*-16}=\frac{-35+\sqrt{1001}}{-32}
$